## Precalculus: Mathematics for Calculus, 7th Edition

Simplify the given equation: 1. $1-[2-(3-x)]=4x-(6+x)$ 2. Distribute the negative sign inside of the brackets:$1-(2-3+x) = 4x-(6+x)$ 3. Distribute the negative signs on the left and right side of the equation: $1-2+3-x=4x-6-x$ 4. Simplify both sides of the equation: $2-x=3x-6$5. Add 6 to both sides of the equation:$8-x=3x$ 5. Add x to both sides of the equation: $8=4x$ a. Plug in x=2 to see if it makes the equation true: $8=4(2)$ $8=8$ the equation is true so yes, x=2 is a solution of the given equation. b. Plug in $x=4$ to see if it makes the equation true: $8=4(4)$ $8=16$ the equation is not true so x=4 is not a solution of the given equation.