# Chapter 1 - Section 1.5 - Equations - 1.5 Exercises: 45

The real solutions of the equation $x^{2}+x-12$ are x=-4,3.

#### Work Step by Step

1. Factor $x^{2}+x-12$: The factors are $(x-3)(x+4)$ because $-3\times 4$ = -12 (the c value in $a^{2}+bx+c$ and -3+4 =1, the b value. 2. Set x-3 and x-4 equal to zero and solve: $x=3, x=-4$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.