## Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole

# Chapter 1 - Section 1.5 - Equations - 1.5 Exercises: 24

#### Answer

$x=\dfrac{1}{17}$

#### Work Step by Step

$2x-\dfrac{x}{2}+\dfrac{x+1}{4}=6x$ Multiply the whole equation by $4$, which is the least common multiple of the denominators present in the equation. We will do this to avoid working with fractions. $(2x-\dfrac{x}{2}+\dfrac{x+1}{4}=6x)(4)$ $8x-(4)(\dfrac{x}{2})+(4)(\dfrac{x+1}{4})=24x$ $8x-2x+x+1=24x$ Take all the terms with $x$ to the left side and take the $1$ to the right side: $8x-2x+x-24x=-1$ Simplify: $-17x=-1$ Solve for $x$: $x=\dfrac{-1}{-17}=\dfrac{1}{17}$

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