Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises: 35

Answer

$x = \frac{2d-b}{a-2c}$

Work Step by Step

$Solve$ $the$ $equation$ $for$ $the$ $indicated$ $variable:$ $\frac{ax + b}{cx + d} = 2;$ $for$ $x$ Solve for x Multiply both sides by $cx + d$ $cx+d(\frac{ax + b}{cx + d}) = 2(cx+d)$ Simplify $ax+b = 2cx + 2d$ Subtract 2cx from both sides $ax+b - 2cx = 2cx + 2d - 2cx$ $ax+b - 2cx = 2d$ Subtract b from both sides $ax + b - 2cx - b = 2d - b$ $ax - 2cx = 2d - b$ Factor out $x$ from $ax-2cx$ $x(a-2c) = 2d-b$ Divide both sides by $(a-2c)$ $\frac{x(a-2c)}{a-2c} = \frac{2d-b}{a-2c}$ $x = \frac{2d-b}{a-2c}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.