## Precalculus: Mathematics for Calculus, 7th Edition

$\frac{x}{3}-2=\frac{5}{3}x+7$ Solution: $x=-\frac{27}{4}$
1. $\frac{x}{3}-2=\frac{5}{3}x+7$ 2. Add 2 to both sides: $\frac{x}{3}=\frac{5}{3}x+9$ 3. Multiply each side by 3: $x=5x+27$ 4. Subtract $5x$ from each side:$-4x=27$ 5. Divide both sides by -4: $x=-\frac{27}{4}$