Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises: 75

Answer

$\sqrt[12]{2}$

Work Step by Step

RECALL: $\sqrt[m]{\sqrt[n]{a}}=\sqrt[mn]{a}$ Use the rule above to obtain: $=\sqrt[4(3)]{2} \\=\color{blue}{\sqrt[12]{2}}$
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