Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 75: 45

Answer

$\color{blue}{\sqrt{42pqr}}$

Work Step by Step

Use the rule $\sqrt{a}\cdot \sqrt{b}=\sqrt{ab}, a\gt0, b\gt0$ to obtain: $=\sqrt{14(3pqr)} \\=\color{blue}{\sqrt{42pqr}}$
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