Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 75: 78

Answer

$\color{blue}{11\sqrt{2k}}$

Work Step by Step

Simplify each radical. Factor the radicand so that one factor is a perfect square, then bring out the square root of the perfect square factor to obtain: $=4\sqrt{9(2k)}-\sqrt{36(2k)} +\sqrt{25(2k)} \\=4\cdot 3\sqrt{2k}-6\sqrt{2k}+5\sqrt{2k} \\=12\sqrt{2k}-6\sqrt{2k}+5\sqrt{2k}$ Combine like terms to obtain: $=(12-6+5)\sqrt{2k} \\=\color{blue}{11\sqrt{2k}}$
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