Answer
$\color{blue}{12\sqrt{2x}}$
Work Step by Step
Simplify each radical.
Factor the radicand so that one factor is a perfect square, then bring out the square root of the perfect square factor to obtain:
$=8\sqrt{2x}-\sqrt{4(2x)} +\sqrt{36(2x)}
\\=8\sqrt{2x}-2\sqrt{2x}+6\sqrt{2x}$
Combine like terms to obtain:
$=(8-2+6)\sqrt{2x}
\\=\color{blue}{12\sqrt{2x}}$
