Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises: 77

Answer

$\color{blue}{12\sqrt{2x}}$

Work Step by Step

Simplify each radical. Factor the radicand so that one factor is a perfect square, then bring out the square root of the perfect square factor to obtain: $=8\sqrt{2x}-\sqrt{4(2x)} +\sqrt{36(2x)} \\=8\sqrt{2x}-2\sqrt{2x}+6\sqrt{2x}$ Combine like terms to obtain: $=(8-2+6)\sqrt{2x} \\=\color{blue}{12\sqrt{2x}}$
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