Answer
$\color{blue}{3\sqrt[3]{3}}$
Work Step by Step
Factor the radicand so that one factor is a perfect cube to obtain:
$=\sqrt[3]{27(3)}
\\=\sqrt[3]{3^3(3)}$
Bring out the cube root of the perfect cube factor to obtain:
$=\color{blue}{3\sqrt[3]{3}}$
