Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises: 50

Answer

$\color{blue}{-\dfrac{4}{7}}$

Work Step by Step

Since $\dfrac{16}{49} = \left(\dfrac{4}{7}\right)^2$, the given expression simplifies to: $=-\sqrt{\left(\dfrac{4}{7}\right)^2} \\=\color{blue}{-\dfrac{4}{7}}$
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