Answer
$$\frac{1}{2}$$
Work Step by Step
$$\frac{-(q-6)^2-2p}{4-p}$$
$$\frac{-(8-6)^2-2(-4)}{4-(-4)}$$
$$\frac{-4+8}{8}$$
$$\frac{4}{8}$$
$$\frac{1}{2}$$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.2 Real Numbers and Their Properties - R.2 Exercises - Page 20: 46
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