Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.2 Real Numbers and Their Properties - R.2 Exercises: 42

Answer

3

Work Step by Step

$$p=-4,q=8,r=-10$$ $$\frac{3q}{3p-2r}$$ $$\frac{3(8)}{3(-4)-2(-10)}$$ $$\frac{24}{-12+20}$$ $$\frac{24}{8}$$ $$3$$
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