Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.2 Real Numbers and Their Properties - R.2 Exercises - Page 20: 47

Answer

$$6$$

Work Step by Step

$$\frac{3p+3(4+p)^3}{r+8}$$ $$\frac{3(-4)+3(4+(-4))^3}{-10+8}$$ $$\frac{-12}{-2}$$ $$6$$
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