Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.2 Real Numbers and Their Properties - R.2 Exercises - Page 20: 34

Answer

$$\frac{6}{5}$$

Work Step by Step

$$\frac{15\div5\times4\div6-8}{-6-(-5)-8\div2}$$ $$\frac{3\times4\div6-8}{-6-(-5)-8\div2}$$ $$\frac{12\div6-8}{-6-(-5)-8\div2}$$ $$\frac{2-8}{-6-(-5)-8\div2}$$ $$\frac{-6}{-6-(-5)-8\div2}$$ $$\frac{-6}{-6-(-5)-4}$$ $$\frac{-6}{-1-4}$$ $$\frac{-6}{-5}$$ $$\frac{6}{5}$$
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