Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.2 Real Numbers and Their Properties - R.2 Exercises - Page 20: 40

Answer

$$\frac{-71}{20}$$

Work Step by Step

$$p=-4,q=8,r=-10$$ $$\frac{3r}{q}-\frac{2}{r}$$ $$\frac{3(-10)}{8}-\frac{2}{-10}$$ $$\frac{-30}{8}+\frac{2}{10}$$ $$\frac{-150}{40}+\frac{8}{40}$$ $$\frac{-142}{40}$$ $$\frac{-71}{20}$$
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