## Precalculus (6th Edition)

$$\frac{-22}{6}$$
$$p=-4,q=8,r=-10$$ $$\frac{\frac{q}{2}-\frac{r}{3}}{\frac{3p}{4}+\frac{q}{8}}$$ $$\frac{\frac{8}{2}-\frac{-10}{3}}{\frac{-12}{4}+\frac{8}{8}}$$ $$\frac{\frac{24}{6}+\frac{20}{6}}{\frac{-24}{8}+\frac{8}{8}}$$ $$\frac{\frac{44}{6}}{\frac{-16}{8}}$$ Dividing Fraction A by Fraction B is the same as multiplying Fraction A by the reciprocal of Fraction B. $$\frac{44}{6}\times\frac{-8}{16}$$ $$\frac{-352}{96}$$ $$\frac{-22}{6}$$