Answer
$\frac{\sqrt 3}{2}$, $\frac{1}{2}$, $\sqrt 3$, $\frac{\sqrt 3}{3}$, $2$, and $\frac{2\sqrt 3}{3}$.
Work Step by Step
Given $\theta=-1020^\circ=-3\times360^\circ+60^\circ$ (quadrant I, reference angle $60^\circ$), we have $sin\theta =sin60^\circ=\frac{\sqrt 3}{2}$, $cos\theta =cos60^\circ=\frac{1}{2}$, $tan\theta =tan60^\circ=\sqrt 3$, $cot\theta = \frac{1}{tan\theta}=\frac{\sqrt 3}{3}$, $sec\theta = \frac{1}{cos\theta}=2$, and $csc\theta = \frac{1}{sin\theta}=\frac{2\sqrt 3}{3}$.
