Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 533: 66

Answer

$-\frac{1}{2}$, $-\frac{\sqrt 3}{3}$, and $-2$.

Work Step by Step

Given $\theta=120^\circ$, we have $cos\theta =-cos60^\circ=-\frac{1}{2}$, $cot\theta = \frac{1}{tan\theta}=-\frac{\sqrt 3}{3}$, and $sec\theta=\frac{1}{cos\theta}=-2$.
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