Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 533: 83

Answer

$-\frac{1}{2}$, $-\frac{\sqrt 3}{2}$, $\frac{\sqrt 3}{3}$, $\sqrt 3$, $-\frac{2\sqrt 3}{3}$, and $-2$.

Work Step by Step

Given $\theta=-510^\circ=-360^\circ-150^\circ$ (quadrant III, reference angle $30^\circ$), we have $sin\theta =-sin30^\circ=-\frac{1}{2}$, $cos\theta =-cos30^\circ=-\frac{\sqrt 3}{2}$, $tan\theta =tan30^\circ=\frac{\sqrt 3}{3}$, $cot\theta = \frac{1}{tan\theta}=\sqrt 3$, $sec\theta = \frac{1}{cos\theta}=-\frac{2\sqrt 3}{3}$, and $csc\theta = \frac{1}{sin\theta}=-2$.
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