Answer
$\frac{\sqrt 3}{2}$, $-\frac{1}{2}$, $ -\sqrt 3$, $ -\frac{\sqrt 3}{3}$, $ -2$, and $ \frac{2\sqrt 3}{3}$.
Work Step by Step
Given $\theta=480^\circ=360^\circ+120^\circ$ (quadrant II), we have $sin\theta =sin60^\circ=\frac{\sqrt 3}{2}$, $cos\theta =-cos60^\circ=-\frac{1}{2}$, $tan\theta =-tan60^\circ=-\sqrt 3$, $cot\theta = \frac{1}{tan\theta}=-\frac{\sqrt 3}{3}$, $sec\theta = \frac{1}{cos\theta}=-2$, and $csc\theta = \frac{1}{sin\theta}=\frac{2\sqrt 3}{3}$.
