Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 533: 82

Answer

$-\frac{1}{2}$, $\frac{\sqrt 3}{2}$, $-\frac{\sqrt 3}{3}$, $-\sqrt 3$, $\frac{2\sqrt 3}{3}$, and $-2$.

Work Step by Step

Given $\theta=-390^\circ=-360^\circ-30^\circ$ (quadrant IV), we have $sin\theta =-sin30^\circ=-\frac{1}{2}$, $cos\theta =cos30^\circ=\frac{\sqrt 3}{2}$, $tan\theta =-tan30^\circ=-\frac{\sqrt 3}{3}$, $cot\theta = \frac{1}{tan\theta}=-\sqrt 3$, $sec\theta = \frac{1}{cos\theta}=\frac{2\sqrt 3}{3}$, and $csc\theta = \frac{1}{sin\theta}=-2$.
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