Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 533: 79

Answer

$-\frac{\sqrt 2}{2}$, $-\frac{\sqrt 2}{2}$, $1$, $1$, $-\sqrt 2$, and $-\sqrt 2$.

Work Step by Step

Given $\theta=1305^\circ=3\times360^\circ+225^\circ=3\times360^\circ+180^\circ+45^\circ$ (quadrant III), we have $sin\theta =-sin45^\circ=-\frac{\sqrt 2}{2}$, $cos\theta =-cos45^\circ=-\frac{\sqrt 2}{2}$, $tan\theta =tan45^\circ=1$, $cot\theta = \frac{1}{tan\theta}=1$, $sec\theta = \frac{1}{cos\theta}=-\sqrt 2$, and $csc\theta = \frac{1}{sin\theta}=-\sqrt 2$.
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