Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 457: 63

Answer

(a) $20\ dB$ (b) $30\ dB$ (c) $50\ dB$ (d) $60\ dB$ (e) $3\ dB$

Work Step by Step

Following the definition of Decibel Levels, we have: (a) $d=10\ log(\frac{I}{I_0})=10\ log(\frac{100I_0}{I_0})=10\ log(100)=20\ dB$ (b) $d=10\ log(\frac{I}{I_0})=10\ log(\frac{1000I_0}{I_0})=10\ log(1000)=30\ dB$ (c) $d=10\ log(\frac{I}{I_0})=10\ log(\frac{100000I_0}{I_0})=10\ log(100000)=50\ dB$ (d) $d=10\ log(\frac{I}{I_0})=10\ log(\frac{1000000I_0}{I_0})=10\ log(1000000)=60\ dB$ (e) $\Delta d=10\ log(I_2)-10\ log(I_1)=10\ log(\frac{I_2}{I_1})=10\ log(2)\approx3\ dB$
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