Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 457: 60

Answer

$9.8386$

Work Step by Step

Use a calculator, $ln\ 33+ln\ 568=ln\ (33\times568)\approx9.8386$
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