Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 457: 29

Answer

$ 3.2$

Work Step by Step

Apply logarithmic property : $\log m+ \log n=\log (mn)$ We can write the equation as: $ p(H)=-\log [6.3 \times 10^{-4}] =-[\log 6.3 + \log 10^{-4}]$ Now, apply logarithmic property : $\log a^ b=b \log a$ Therefore, our answer is: $-[\log 6.3 -4 \log 10]=-0.806-4= 3.2$
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