Answer
$1.5$; Bog
Work Step by Step
We are given that $pH$ between $6.0$ and $7.5$ is rich fen and between $6.0$ and $3.0$ is poor fen or less is bog.
Apply logarithmic property : $\log m+ \log n=\log (mn)$
The given expression can be written as:
$pH=-[\log 3.14 + \log 10^{-2}]$
Now, apply logarithmic property : $\log a^ b=b \log a$
Therefore, we have:
$pH=- \log 3.14 - (-2) \log 10$
or, $pH=-\log 3.14 +2 =1.5$
Therefore, our answer is: $1.5$; Bog