Answer
$4.6$; poor fen
Work Step by Step
We are given that $pH$ between $6.0$ and $7.5$ is rich fen and between $6.0$ and $3.0$ is poor fen or less is bog.
Apply logarithmic property : $\log m+ \log n=\log (mn)$
The given expression can be written as:
$pH=-[\log 2.49 + \log 10^{-5}]$
Now, apply logarithmic property : $\log a^ b=b \log a$
Therefore, we have:
$pH=-[\log 2.49 + \log 10^{-5}]=- \log 2.49 - (-5) \log 10$
or, $pH=-\log 2.49 +5 =4.6$
Therefore, our answer is: $4.6$; poor fen