Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 456: 3

$y=\log_{5} (x)$

The inverse can be obtained by swapping $x$ and $y$ and solving for $y$ . Now, we will take $\log_{5}$ of both sides. $x=5^y$ and $\log_{5}5=\log_{5} [5^{y}]....(1)$ Use property: $a=\log_{b} [b^{a}]$ Therefore, the equation (1) yields: $y=\log_{5} (x)$