Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 456: 25

$\approx 0.1803$

Apply logarithmic property : $\log m-\log n=\log (\dfrac{m}{n})$ Re-write as: $\log 518-\log 342=\log (\dfrac{518}{342})=\log (\dfrac{259}{171})$ Now, take logarithmic to the base $10$ and evaluate the result. Therefore, our answer is: $\log_{10} (\dfrac{259}{171}) \approx 0.1803$