Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 456: 24

Answer

$\approx 3.5505$

Work Step by Step

Apply logarithmic property : $\log m+ \log n=\log (mn)$ $\log 296+ \log 12=\log (296 \times 12) = \log 3552$ Now, take logarithmic to the base $10$ and evaluate the result. Therefore, our answer is: $\log_{10} 3552 \approx 3.5505$
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