Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 456: 16

Answer

$1.9731$

Work Step by Step

Apply logarithmic property : $\log a^ b=b \log a$ $\log (94)^{1}=1 \log (94)$ Now, take logarithmic to the base $10$ and evaluate the result by using calculator . Therefore, our answer is: $ \log_{10} (94) \approx 1.9731$
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