Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 456: 21

$ 0.1803$

Apply logarithmic property : $\log (\dfrac{m}{n})=\log m-\log n$ Re-write as: $\log (\dfrac{518}{342})=\log 518-\log 342$ Now, take logarithmic to the base $10$ and evaluate the result. Therefore, our answer is: $\log_{10} (\dfrac{518}{342})=\log_{10} 518-\log_{10} 342 \approx 0.1803$