Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 456: 20

$3.5505$

Apply logarithmic property : $\log (mn)=\log m+\log n$ Re-write as: $\log (296 \times 12)=\log 296+\log 12$ Now, take logarithmic to the base $10$ and evaluate the result. Therefore, our answer is: $\log_{10} (296 \times 12)=\log_{10} 296+\log_{10} 12$ \approx 3.5505$