Answer
See table.
Work Step by Step
Step 1. Given $f(x)=7x^5+6x^4+2x^3+9x^2+x+5$, we can identify 0 sign changes indicating that there will be 0 positive zeros. Put the numbers in the table.
Step 2. $f(-x)=-7x^5+6x^4-2x^3+9x^2-x+5$, we can identify 5 sign changes indicating that there could be 5, 3 or 1 negative zeros. Put the numbers in the table.
Step 3. There should be 5 total zeros. thus the number of nonreal zeros will be the remaining after taking real zeros into account. Complete the table as shown.