Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - 3.3 Zeros of Polynomial Functions - 3.3 Exercises - Page 337: 50

Answer

$x=0$ with a multiplicity of $1$ $x=-5$ with a multiplicity of $1$ $x=\pm4$ each with a multiplicity of $1$

Work Step by Step

Step 1. Give $f(x)=5x^2(x^2-16)(x+5)$, we can find the first zero as $x=0$ with a multiplicity of $1$ Step 2. We can find the second zero as $x=-5$ with a multiplicity of $1$ Step 3. Let $(x^2-16)=0$, we have $x=\pm4$ each with a multiplicity of $1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.