Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.1 Rectangular Coordinates and Graphs - 2.1 Exercises - Page 194: 49

Answer

$\bf \color {blue}{(0,\frac{5}{3}),(\frac{5}{2},0),(4,-1)\text{ or any other points on the line}}$

Work Step by Step

$$2x+3y=5$$ $\bf \text{Lets plug in numbers to find three points}$ If $x=0$ $3y=5$ $y=\frac{5}{3}$ $\bf \color {blue}{(0,\frac{5}{3})}$ If $y=0$ $2x=5$ $x=\frac{5}{2}$ $\bf \color {blue}{(\frac{5}{2},0)}$ If $x=4$ $2(4)+3y=5$ $8+3y=5$ $3y=-3$ $y=-1$ $\bf \color {blue}{(4,-1)}$ So three of the points are: $\bf \color {blue}{(0,\frac{5}{3}),(\frac{5}{2},0),(4,-1)}$ Which we can graph as a line:
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