Answer
$(\frac{14}{3},\frac{19}{3})$ and $(\frac{28}{3},\frac{38}{3})$
Work Step by Step
Step 1. Given the endpoints $(4,5)$ and $(10,14)$, the first point which is at $1/3$ of the total distance from the start can be found as: $(\frac{4+10}{3},\frac{5+14}{3})$ which gives $(\frac{14}{3},\frac{19}{3})$
Step 2. the second point which is at $2/3$ of the total distance from the start can be found as: $(\frac{2(4+10)}{3},\frac{2(5+14)}{3})$ which gives $(\frac{28}{3},\frac{38}{3})$