Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.1 Rectangular Coordinates and Graphs - 2.1 Exercises - Page 194: 50

Answer

$\bf \color {blue}{(0,-3),(2,0),(1, -\frac{3}{2})}$ $\bf \color {blue}{\text{or any other point on the line}}$

Work Step by Step

$$\bf{3x - 2y = 6}$$ $\bf \text{Lets plug in numbers to find three points}$ if $x=0$: $3(0) - 2y = 6$ $- 2y = 6$ $y = -3$ $\bf \color {blue}{(0,-3)}$ if $y=0$: $3x - 2(0) = 6$ $3x= 6$ $x= 2$ $\bf \color {blue}{(2,0)}$ if $x=1$: $3(1) - 2y = 6$ $3 - 2y = 6$ $- 2y = 3$ $y = -\frac{3}{2}$ $\bf \color {blue}{(1, -\frac{3}{2})}$ So three of the points are: $\bf \color {blue}{(0,-3),(2,0),(1, -\frac{3}{2})}$ Which we can graph as a line:
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