Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.1 Rectangular Coordinates and Graphs - 2.1 Exercises - Page 194: 53

Answer

$\bf \color {blue}{(3,0),(4,1),(7,2)}$

Work Step by Step

$$\bf{y = \sqrt{x - 3}}$$ $\bf \text{Lets plug in numbers to find three points}$ if $y=0$: $0 = \sqrt{x - 3}$ $0 = x - 3$ $x = 3$ $\bf \color {blue}{(3,0)}$ if $y=1$: $1 = \sqrt{x - 3}$ $1 = x - 3$ $x = 4$ $\bf \color {blue}{(4,1)}$ if $y=2$: $2 = \sqrt{x - 3}$ $4 = x - 3$ $x =7$ $\bf \color {blue}{(7,2)}$ So three of the points are: $\bf \color {blue}{(3,0),(4,1),(7,2)}$ Which we can graph:
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