Answer
$\bf \color {blue}{(0,0),(-1,1),(1,-1),(-2,8),(2,-8)}$
Work Step by Step
$$\bf{y=-x^3}$$
$\bf \text{Let's use positive and negative perfect cubes for y}$
if $y=0$:
$0=-x^3$
$0=x$
$\bf \color {blue}{(0,0)}$
if $y=\pm1$:
$1=-x^3$ or $-1=-x^3$
$-1=x^3$ or $1=x^3$
$-1=x$ or $1=x$
$\bf \color {blue}{(-1,1),(1,-1)}$
if $y=\pm8$:
$8=-x^3$ or $-8=-x^3$
$-8=x^3$ or $8=x^3$
$-2=x$ or $2=x$
$\bf \color {blue}{(-2,8),(2,-8)}$
So some of the points are:
$\bf \color {blue}{(0,0),(-1,1),(1,-1),(-2,8),(2,-8)}$
Which we can graph as:
