Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.1 Rectangular Coordinates and Graphs - 2.1 Exercises - Page 194: 48

Answer

$\bf \color {blue}{(0,2),(4,0),(2,1)}$

Work Step by Step

$y=-\frac{1}{2}x+2$ $\bf \text{Let's plug in numbers to find three points}$ if $x=0$: $y=-\frac{1}{2}(0)+2$ $y=2$ $\bf \color {blue}{(0,2)}$ if $y=0$: $0=-\frac{1}{2}x+2$ $4=x$ $\bf \color {blue}{(4,0)}$ if $x=2$: $y=-\frac{1}{2}(2)+2$ $y=-1+2$ $y=1$ $\bf \color {blue}{(2,1)}$ So our three points are: $\bf \color {blue}{(0,2),(4,0),(2,1)}$ Which we can graph as a line
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