Answer
$\color{blue}{[3,6]}$
Work Step by Step
Subtract $4$ to each part:
\begin{array}{ccccc}
&10-4 &\le &2x+4-4 &\le &16-4
\\&6 &\le &2x &\le &12
\end{array}
Divide each part by $2$:
\begin{array}{ccccc}
\\&\frac{6}{2} &\lt &\frac{2x}{2} &\lt &\frac{12}{2}
\\&3 &\lt &x &\lt &6
\end{array}
Thus, the solution to the given inequality in interval notation is: $\color{blue}{[3,6]}$
