Answer
$\color{blue}{\left(-\infty, \dfrac{15}{7}\right)}$
Work Step by Step
Distribute $5$ and $-6$ to obtain:
$2-4x+5(x) -5(1)\lt -6(x)-(-6)(2)
\\2-4x+5x-5 \lt -6x -(-12)
\\x-3 \lt -6x+12$
Add $6x$ and $3$ to both sides, then combine like terms to obtain:
$x-3 +6x+3 \lt -6x+12+6x+3
\\7x \lt 15$
Divide $7$ to both sides of thee equation to obtain:
$\dfrac{7x}{7} \lt \dfrac{15}{7}
\\x \lt \dfrac{15}{7}$
Thus , the solution set is:
$\color{blue}{\left(-\infty, \dfrac{15}{7}\right)}$
