Answer
$\color{blue}{(-\infty, +\infty)}$
Work Step by Step
Distribute $3$ to obtain:
$3(x) + 3(5)+1 \ge 5+3x
\\3x+15+1 \ge 5+3x
\\3x+16 \ge 5+3x$
Subtract $16$ and $3x$ to both sides, then combine like terms to obtain:
$3x+16-16-3x\ge 5+3x-16-3x
\\0\ge -11$
The resulting statement above is true, which means that any real numbers is a solution.
Thus , the solution set is:
$\color{blue}{(-\infty, +\infty)}$
