Answer
$\color{blue}{(\frac{1}{6}, 1)}$
Work Step by Step
Subtract $3$ to each part:
\begin{array}{ccccc}
&2-3&\gt &-6x+3-3 &\gt &-3-3
\\&-1 &\gt &-6x &\gt &-6
\end{array}
Divide each part by $-6$.
Note that since a negative number is divided to the inequality, the inequality symbol will be reversed.
\begin{array}{ccccc}
\\&\frac{-1}{-6} &\lt &\frac{-6x}{-6} &\lt &\frac{-6}{-6}
\\&\frac{1}{6} &\lt &x &\lt &1
\end{array}
Thus, the solution to the given inequality is:
$\color{blue}{(\frac{1}{6}, 1)}$
