Answer
$\color{blue}{[-4 , +\infty)}$
Work Step by Step
Subtract $8$ to both sides:
$-2x+8-8 \le 16-8
\\-2x \le 8$
Divide $-2$ to both sides.
Since a negative number was divided to both sides of the inequality, the inequality symbol will be reversed.
$\dfrac{-2x}{-2} \ge \dfrac{8}{-2}
\\x \ge -4$
In interval notation, the solution set is:
$\color{blue}{[-4 , +\infty)}$
