Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set: 48

Answer

$\log{\frac{3x+7}{x}}$

Work Step by Step

RECALL: (i) $\log_b{M} - \log_b{N} = \log_b{\frac{M}{N}}.$ (ii) $\log_b{b^x}=x.$ Use rule (i) above with $M=3x+7$ and $N=x$ to obtain $\log{\frac{3x+7}{x}}.$
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