Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set - Page 475: 76

Answer

$-2.4456$

Work Step by Step

Apply the Change of base property: $\displaystyle \quad \log_{b}M=\frac{\log_{a}M}{\log_{a}b}$ Change to base 10 (common logarithm) $\displaystyle \log_{0.3}19=\frac{\log 19}{\log 0.3}\approx-2.4456$
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