## Precalculus (6th Edition) Blitzer

$\log_8{13} + \log_8{7}$
RECALL: $\log_b{MN}=\log_b{M} + \log_b{N}$ (Product Rule). Use the product rule with $M=13$ and $N=7$ to obtain $\log_8{13} + \log_8{7}.$